From the problem, the distance travelled is 720 miles.
Let 2x be the speed of the corporate jet
and
x be the speed of the smaller plane, since smaller plane can fly half as fast as the corporate jet.
Let y be the travel time of the corporate jet
and 6 - y be the travel time of the smaller plane since the total time is 6 hours
The working equation is :
speed x time = distance
For the corporate plane :
![\begin{gathered} \text{speed}*\text{time}=\text{distance} \\ 2x\mleft(y\mright)=720 \\ 2xy=720 \\ xy=(720)/(2)=360 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5sn35xeumopofr6jymipg1hk1ihco8gkw4.png)
For the smaller plane :
![\begin{gathered} \text{speed}*\text{time}=\text{distance} \\ x(6-y)=720 \\ 6x-xy=720 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/xijqdew1kn9kb70oomiw1t5zq6odcmdrwe.png)
Substitute xy = 360 to the 2nd equation :
![\begin{gathered} 6x-xy=720 \\ 6x-360=720 \\ 6x=720-360 \\ 6x=360 \\ x=(360)/(6)=60 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/i0dhs7kxai47ys411hf1lii9fi7xkg8aef.png)
x = 60 which is the speed of the smaller plane
The speed of the corporate plane will be :
2x = 2(60) = 120
The answer :
corporate jet = 120 mph
smaller plane = 60 mph