For the first right triangle
the points of the hypotenuse
(0,3)=(x1,y1)
(7,0)=(x2,y2)
the slope of the hypotenuse is
![m=(y_2-y_1)/(x_2-x_1)=(0-3)/(7-0)=(-3)/(7)=-(3)/(7)](https://img.qammunity.org/2023/formulas/mathematics/college/6qzt639s8n6fa3yjx2eqpu0lfvyc3vsf2d.png)
and the equation of the hypotenuse
![y=-(3)/(7)x+3](https://img.qammunity.org/2023/formulas/mathematics/college/5k329izbo2zv1o9sd940m03dbtcea7adrp.png)
For the second triangle
The points of the hypotenuse
(0,9)
(21,0)
![m=(0-9)/(21-0)=(-9)/(21)=-(3)/(7)](https://img.qammunity.org/2023/formulas/mathematics/college/x2dkthh582dhxyq97e0b9nusj0mxsv5ijo.png)
and the equation of the hypotenuse
![y=-(3)/(7)x+9](https://img.qammunity.org/2023/formulas/mathematics/college/asa6n8x7erbkduz68tna1fn5ffoe7gmpxy.png)
The equations are not equal but they have the same slope, which indicates that the equations are parallels.
The answer is
No, because one is larger than the other