Question

I'm trying ways to solve it but I keep getting it wrong. May you please help me

Answer 1

x=-2

y=-1

(-2,-1)

Step-by-step explanation

Step 1

Let

`\begin{gathered} 5x+4y=-14\text{ Equation(1)} \\ y=-7x-15\text{ Equation(2)} \end{gathered}`

Step 2

substitute the value of y , form equation (1) in equation(2)

`\begin{gathered} 5x+4y=-14 \\ \text{then} \\ 5x+4(-7x-15)=-14 \end{gathered}`

Step 3

apply the distributive property to eliminate the parenthesis

`\begin{gathered} 5x+4(-7x-15)=-14 \\ 5x-28x-60=-14 \\ -23x-60=-14 \end{gathered}`

Step 4

add 60 in both sides

`\begin{gathered} -23x-60=-14 \\ -23x-60+60=-14+60 \\ -23x=46 \end{gathered}`

Step 5

finally, divide each side by -23

`\begin{gathered} -23x=46 \\ (-23x)/(-23)=(46)/(-23) \\ x=-2 \end{gathered}`

Step 6

Finally, replace the value of x=-2 in equation (2) to find y

`\begin{gathered} y=-7x-15 \\ y=-7(-2)-15 \\ y=14-15 \\ y=-1 \end{gathered}`

so, the answer is (-2,-1)