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A standard roulette wheel contains the numbers 1-36, and two spaces marked "0" and "00." Halfof the numbers are labeled black, and half of the numbers are labeled red. The numbers "0" and"00" are labeled green. Half of the red and black slots have even numbers, the other half oddnumbers. When the wheel is spun, a ball rolls along the outer edge of the wheel until it falls intoone of the numbered slots. What is the probability that the ball lands on a number 1-8 inclusive ora number 11-25 inclusive?

User Pritaeas
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1 Answer

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Probabilities

The standard roulette has 36 spaces for numbers 1 to 36 and two spaces for the "0" and "00" for a total of 38 spaces.

We are required to calculate the probability that the ball falls into a number 1 to 8 or a number 11-25.

There are 8 - 1 + 1 = 8 favorable outcomes in the first option and 25 - 11 + 1 = 15 favorable outcomes.

The total favorable outcomes is 8 + 15 = 23

Thus, the required probability is:


p=(23)/(38)

Calculating:

p = 0.6053

p = 60.53%

User SuperNES
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