Part 1.
For a vector

its magnitude is written as

and is given by
![|\vec{v}|=\sqrt[]{x^2+y^2}](https://img.qammunity.org/2023/formulas/mathematics/college/69rofsruwe91uyjm7mh75cerz7s8fvbka3.png)
This formula comes from Pythagorean theorem:
Therefore, the answer for part A is:
![|\vec{v}|=\sqrt[]{x^2+y^2}](https://img.qammunity.org/2023/formulas/mathematics/college/69rofsruwe91uyjm7mh75cerz7s8fvbka3.png)
Part B.
Now, we can use the above result into the given vector. Then, the magnitude of vector u is
![\begin{gathered} |\vec{u}|=\sqrt[]{4^2+7^2} \\ |\vec{u}|=\sqrt[]{16^{}+49} \\ |\vec{u}|=\sqrt[]{65} \\ |\vec{u}|=8.0623 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/sq1xuyluj0hb1od77vqjoaeshsyqjz83vr.png)
Then, the answer for part B is:
