Question

DАсBIf mZACB = 180°, and m2DCB = 135°,then m DCA = [?]°

Answer 1

from the information given in the question we have the following

as given in the question

`\begin{gathered} \angle\text{ ACB = 180}^(\circ) \\ \angle DCB=135^(\circ) \\ \end{gathered}`

We are to find angle DCA

Using the property of straight line

`\begin{gathered} \angle ACB\text{ = }\angle DCA\text{ + }\angle\text{DCB }(Sum\text{ of angles on a straight line = 180)} \\ 180^(\circ)\text{ = }\angle DCA\text{ + }135^(\circ) \\ 180^(\circ)-135^(\circ)\text{ = }\angle DCA \\ \angle DCA=45^(\circ) \end{gathered}`

Therefore,

angle