Remember that te square root of 11 is a number such that when it is multiplied by itself, the result is 11.
Since the function f(x)=x^2 is an increasing function from 0 onwards, then if 0[tex]a^2Let x be the square root of 11. Find two whole numbers a and b such that:
[tex]a^2<11Since 3^2=9 and 4^2=16, then the square root of 11 should be somewhere between 3 and 4.