Answer:
782.58 N
Step-by-step explanation:
By the second law of Newton, at the bottom of the swing path, the net force is equal to
![\begin{gathered} F_(net)=T-mg=ma \\ \\ T-mg=m(v^2)/(r) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/fdnbvw1ml4kyu95mieyvrq8q0u1rl5kjre.png)
Since a is the centripetal acceleration, we get that a = v²/r. Where v is the speed and r is the length of the hair.
Solving for the tension T, we get:
![T=m(v^2)/(r)+mg](https://img.qammunity.org/2023/formulas/physics/college/fzpi8v3vsc4h3wx5y7xpy0rge5c6kev529.png)
Now, we can replace m = 51 kg, v = 6.5 m/s, g = 9.8 m/s² and we can convert r = 25 feet to meters as
![25\text{ feet}*\frac{1\text{ m}}{3.281}=7.62\text{ m}](https://img.qammunity.org/2023/formulas/physics/college/lnxt2s55lf6jb3x1jrec0d5z5i9if01eu2.png)
Then, the tension is equal to
![\begin{gathered} T=(51\text{ kg\rparen}\frac{(6.5\text{ m/s\rparen}^2}{7.62\text{ m}}+(51\text{ kg\rparen\lparen9.8 m/s}^2) \\ \\ T=782.58\text{ N} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/h87moyttt7p3rcnihek8cmxmjxf06prp2j.png)
Therefore, the tension is 782.58 N