We will have the points (0, 50) & (2, 100), using this we can find a linear equation that models the money over time. We first find the slope:

Now, using one of the points we replace in:

We will use (0, 50), but we could use any other point of the line. Now, we replace:

And now, we solve for y:

Now, in order to get the saving for each month, we replace x by 5, 10, 15 & 20 respectively:
*5 weeks:

*10 weeks:

*15 weeks:

*20 weeks:

From this, we have that the savings for 5, 10, 15 & 20 weeks are 175, 300, 425 & 550 respectively.