Given,
The magnitude of vector A, A=4.00 units
The magnitude of vector B, B=5.40 units
The angle between A and B, θ=60.0°
The magnitude of the sum of two vectors is given by,
![|\vec{A}+\vec{B}|=\sqrt[]{A^2+B^2+2AB\cos \theta}](https://img.qammunity.org/2023/formulas/physics/college/6mexgc3b20sng3y0af8spi1siwgdwutmuf.png)
On substituting the known values,
![\begin{gathered} |\vec{A}+\vec{B}|=\sqrt[]{4.00^2+5.40^2+2*4.00*5.40*\cos 60^(\circ)} \\ =8.17\text{ units} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/uz097bzzmahk4ampwn3qjm36swrq569a56.png)
Therefore, the magnitude of the sum of the two given vectors is 8.17 units