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A student in the laboratory connects a 20 Ω resistor, a 30 Ω resistor, and a 42 Ω resistor in series and then connects the arrangement to a 65-V dc source.(a) How much current is in the circuit? ________:A(b) How much power is expended in the circuit? _________:W

User Saljuama
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1 Answer

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First, let's calculate the equivalent resistance of the three series resistances:


\begin{gathered} R_(eq)=R_1+R_2+R_3\\ \\ R_(eq)=20+30+42\\ \\ R_(eq)=92\text{ \Omega} \end{gathered}

(a)

To calculate the current in the circuit, we can use Ohm's Law:


\begin{gathered} I=(V)/(R)\\ \\ I=(65)/(92)\\ \\ I=0.7065\text{ A} \end{gathered}

(b)

To calculate the power expended in the circuit, we can use the formula below:


\begin{gathered} P=I\cdot V\\ \\ P=0.7065\cdot65\\ \\ P=45.92\text{ W} \end{gathered}

User Basanth Roy
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