The Probability of getting at least one head when tossing four fair coins is 15/16
Step-by-step explanation:
A coin as a head and a tail
Probability of getting a head = 1/2
Probability of getting a tail = 1 - 1/2 = 1/2
We need to find the probability of getting at least 1 head when tossing 4 coins.
To do this, we will apply the "at least once" rule
At least once rule states that:

