Question

Pls I don’t have much time explain it clearly thank u.

Answer 1

`40v^6u^(13)`

Step-by-step explanation

let's remember how to multiply terms with variables and exponents

let

a, b, c,m, n ,o and p integers

x and y variables, so

`\begin{gathered} ax^m\cdot bx^n=(a\cdot b)x^(m+n) \\ \text{also} \\ ax^my^n\cdot bx^oy^p=(a\cdot b)x^(m+o)y^(n+p) \end{gathered}`

Step 1

hence, do the operation usign the properties

`\begin{gathered} 4v^5u^7\cdot2v\cdot5u^6 \\ 4v^5u^7\cdot2v\cdot5u^6=(4\cdot2\cdot5)v^(5+1)u^(7+6) \\ 4v^5u^7\cdot2v\cdot5u^6=(40)v^6u^(13) \\ 4v^5u^7\cdot2v\cdot5u^6=40v^6u^(13) \end{gathered}`

therefore, the answer is

`40v^6u^(13)`

i hope this helps yo