Question

Solve the system of equations algebraically.x + 3y = -14-x + 3y = - 10

Answer 1

x=-2, y=-4.

Step-by-step explanation:

Given the system of equations:

`\begin{gathered} x+3y=-14 \\ -x+3y=-10​ \end{gathered}`

Add the two equations to eliminate x:

`\implies6y=-24`

Divide both sides by 6 to solve for y:

`\begin{gathered} y=-(24)/(6) \\ y=-4 \end{gathered}`

Next, substitute y=-4 into any of the equations to solve for x:

`\begin{gathered} x+3y=-14 \\ x+3(-4)=-14 \\ x-12=-14 \\ x=-14+12 \\ x=-2 \end{gathered}`

The solution to the system is: x=-2, y=-4.