The surface area of a sphere can be calculated using this formula:

Where "r" is the radius of the sphere.
In this case, knowing that:

You can substitute this value into the formula and solve for the radius "r". Then, you get:
![\begin{gathered} 38\pi\text{ }in^2=4\pi r^2 \\ \\ \frac{38\pi\text{ }in^2}{4\pi}=r^2 \\ \\ \sqrt[]{\frac{38\pi\text{ }in^2}{4\pi}}=r \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/emkjbbj43xf4plviww38pxwzodgcffvbj8.png)

Therefore, the answer is:
