Answer:
0.5417
Step-by-step explanation:
The frictional force is equal to the coefficient of kinetic friction times the normal force, so
![F_f=\mu_kF_n](https://img.qammunity.org/2023/formulas/physics/college/nxr8i05t1d1sfck1stsvwohaozm46d1efe.png)
Then, solving for the coefficient of kinetic friction, we get:
![\mu_k=(F_f)/(F_n)](https://img.qammunity.org/2023/formulas/physics/college/es9zd31t04q7cz2qyjye1oiuje9ttl1rad.png)
Now, we can replace the frictional force Ff by 65 N and the normal force Fn by 120 N
![\mu_k=(65N)/(120N)=0.5417](https://img.qammunity.org/2023/formulas/physics/college/u4t4ui12tejozdiofau4vjptqxbqw4mbt2.png)
Therefore, the coefficient of kinetic friction is 0.5417