Question

Gary has these cans of soup in his kitchen cabinet . Gary will randomly choose one can of soup to eat for lunch . the next day you will randomly choose another can of soup. What is the probability that he will choose a can of chicken soup the first day, and a can of potato soup the next day?

Answer 1

Answer: 1/15

Given data

2 cans of tomato soup

3 can s of chicken soup

2 cans of cheese soup

2 cans of potato soup

1 can of beef soup

Firstly, we need to calculate the total number of cans of soup

Total number of cans of soup = 2 + 3 + 2+ 2+ 1

Total number of cans of soup = 10

Probability of chosen a can of schicken soup = 3/ 10

The total number left will be 9 because it is without replacement

Probability of chosen a can of potato soup in the next day = 2/ 9

AND means multiplication

Probability of chosen chicken and potato can of soup =

`\begin{gathered} (3)/(10)\text{ x }(2)/(9) \\ =\text{ }(6)/(90) \\ =\text{ }(1)/(15) \end{gathered}`

Probability of chosen a can of chicken and potato soup is 1/15

What I mean by without replacement is that if you choose a can of chicken soup today out of the total 10 cans of soup,it will remain 9 because after consuming the soup you won't replace the empty can.