Answer:2Al(s) + 3H2SO4(aq) ==> Al2(SO4)3(aq) + 3H2(g) ... balanced equation
Using the stoichiometry of the balanced equation (2 mol Al : 3 mol H2SO4) and dimensional analysis, we can find the mass of Al needed to react with 26.5 ml of 0.542 M H2SO4.
Step-by-step explanation: