Given the amount of strawberries Dedra ate each day:

Let's select the X's from the given chart.
The frequency represents the number of Xs you can select.
Frequency is the number of times a number occurs in a given data.
We have:
Data Frequency
3 1
3⅖ 2
3⅘ 3
4 3
Let's find the median amount of strawberries Dedra ate per day.
To find the median, apply the formula:

Where:
n is the total frequency.
n = 1 + 2 + 3 + 3 = 9
Since n is an odd number, the median will be:
Hence, we have:

The median will be the fifth data.
From the table, the fifth data value is 3⅘.
Therefore, the median amount of strawberries Dedra ate per day is:

ANSWER:
