Given:
Initial value of camera = $1600
Percentage decrease = 12.5% per year = 0.125
Time, t = 5 years
Let's find the value of the camera after the given time (5 years).
To find the value of the camera, apply the exponential decay formula:
![A=P(1-r)^t](https://img.qammunity.org/2023/formulas/mathematics/college/1dz8eletuom10hcjysqttrllohcpvzc4zb.png)
Where:
A is the final value
P is the initial value = $1600
r is the rate of change = 0.125
t is the time = 5 years
Thus, we have:
![\begin{gathered} A=1600(1-0.125)^5 \\ \\ A=1600(0.875)^5 \\ \\ A=1600(0.5129) \\ \\ A=820.65 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/m6vtjh6z32d3bei3yu7sch8rnovosgt236.png)
Therefore, the value of the camera after 5 years will be $820.65
ANSWER:
$820.65