From the given information, we know that
![\begin{gathered} \operatorname{mean}\text{ }\mu=25\text{ } \\ \text{ standard deviation }\sigma=6.1 \end{gathered}]()
In order to find the probability, we need to find the z-score for the measure X=28. The z-score formula is given by

By substituting the given values, we have

Now, we need to find the p-value corresponding to this z-value. Then, we found that

Therefore, by rouding to 4 decimal places, the answer is
