Given: A series 11,15,19,23,27,...
Required: To determine the nth term.
Explanation: The given series is an arithmetic progression with the first term, a=11, and the common difference, d=4.
The formula gives the nth term of an AP-
![a_n=a+(n-1)d](https://img.qammunity.org/2023/formulas/mathematics/high-school/t99kk5roieipg56xa37yseewl9ybc4zh6i.png)
Substituting the values into the formula as-
![a_n=11+(n-1)4](https://img.qammunity.org/2023/formulas/mathematics/high-school/fjzne5pznlth3nh8o9kpwm0u3v5alwl1sy.png)
Further solving-
![\begin{gathered} a_n=11+4n-4 \\ a_n=4n+7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/orkvdpa35rnmdta19cig67ewqzz65olf5s.png)
Final Answer: The nth term of the series is 4n+7.