Question

If (-12, -5) is on the terminal side of 0, then sec 0=

Answer 1

The (-12,-5) indicates the following.

`(-12,-5)=(x,y)`

To determine the value of r, we solve as follows.

`\begin{gathered} r=\sqrt[]{x^2+y^2} \\ r=\sqrt[]{(-12)^2+(-5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ =13 \end{gathered}`

To find the value of secθ, we substitute as follows.

`\sec \theta=(r)/(x)=(13)/(-12)=-(13)/(12)`