Given the curve:

You need to find the equation for the tangent to that curve at the point:

Then, you need to follow these steps:
1. Derivate the function given in the exercise using these Derivative Rules:



Where "k" is a constant.
Then, you get:




2. Substitute this value of the x-coordinate of the given point into the derivated function and then evaluate, in order to find the slope of the line:

4. The Point-Slope Form of the equation of a line is:

Where "m" is the slope of the line and this point is on the line:

In this case:

Therefore, you can substitute values:

5. Convert the equation from Point-Slope Form to Slope-Intercept Form.
The equation of a line in Slope-Intercept Form is:

Where "m" is the slope and "b" is the y-intercept.
Then, by solving for "y", you get:




Hence, the answer is:
1. Derivate the function.
2. Find the slope of the tangent line by substituting the x-coordinate of the given point into the function derivated.
3. Write the equation of the tangent line in Point-Slope Form using the given point and the slope.
4. Rewrite the equation in Slope-Intercept Form by solving for "y".
Equation for the tangent of the curve:
