Question

find the two -intercepts of the function and show that f'(x) = 0 at some point between the two x -intercepts.

Answer 1

When we are given a quadratic function of the form:

`f(x)=ax^2+bx+c`

We can solve for:

`ax^2+bx+c=0`

Using the quadratic formula:

`x_(1,2)=(-b\pm√(b^2-4ac))/(2a)`

Since we want to find the x-intercepts, these are the x such that f(x) = 0. The function given in the problem is: