Solution
- The formula given is
![\begin{gathered} p(t)=800(1.019)^t \\ where, \\ t=\text{ The number of years from today} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gua6gy1upnmhmv4xbaa1gifjuji8kl5aiz.png)
Price for today:
- The number of years from today is 0 years. Implying that
![t=0](https://img.qammunity.org/2023/formulas/mathematics/high-school/hjl3uyxgb078iujqg67x1b4lz4s6l3i8vf.png)
- Thus, we can find the price for today as follows:
![\begin{gathered} p(0)=800(1.019)^0 \\ p(0)=800*1 \\ \\ \therefore p(0)=800 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nrutq7nuewh8cxm51bjjijxue6ffpad2q6.png)
- The cost today is 800
Price 9 years from today:
- The number of years from today is 9 years. Implying that
![t=0](https://img.qammunity.org/2023/formulas/mathematics/high-school/hjl3uyxgb078iujqg67x1b4lz4s6l3i8vf.png)
- Thus, we can find the price 9 years from now as follows:
![\begin{gathered} p(9)=800(1.019)^9 \\ p(9)=947.67 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gsbar1fixpattpvojmq540dkwtbyuidrj2.png)
- The cost 9 years from now is 947.67