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How many mL of water would you add to 20mL of a 7.5M solution of Hydrochloric Acid in order to have a 2M solution?

User Ieshia
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1 Answer

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Step-by-step explanation:

When working with dillutions we usually use this formula.

Vd * Md = Vc * Mc

Where Vc and Mc are the volume and molarity of the concentrated solution and Vd and Md are the volume and molarity of the dilluted solution.

Vd = ? Md = 2 M Vc = 20 mL Mc = 7.5 M

With that formula we can find the volume of the dilluted solution that we can prepare from a determined volume of a concentrated solution.

Vd * Md = Vc * Mc

Vd = Vc * Mc/Md

Vd = 20 mL * 7.5 M/(2 M)

Vd = 75 mL

With the concentrated solution we can prepare 75 mL of the 2 M solution. To prepare that solution we will add some mL of water to the concentrated solution that already had a volume of 20 mL.

Vdilluted = Vwater + Vconcentrated

Vwater = Vd - Vc

Vwater = 75 mL - 20 mL

Vwater = 55 mL

Answer: we have to add 55 mL of water to the 7.5 M solution.

User Anubhava
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