Question

A circuit with a battery, a 6 Ω resistor, a 12 Ω resistor, and a 22 Ω resistor in parallel. The total voltage is the system is 8.9 V. What is the current through the 6 Ω resistor?

Answer 1

The current through a resistor with resistance R connected to a voltage V can be found using the following expression:

`I=(V)/(R)`

Since all the resistors are connected in parallel, then the voltage through each of them is the same.

Replace V=8.9V and R=6Ω to find the current through the 6Ω resistor:

`I=(8.9V)/(6\Omega)=1.48333\ldots A\approx1.5A`

Therefore, the current through the 6Ω resistor is approximately 1.5A.