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Factor Sums and Differences of Cubes 125-27w^3
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Factor Sums and Differences of Cubes 125-27w^3

User AfamO
by
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1 Answer

4 votes

Solution

Given


125-27w^3

Recall that


(a^3-b^3)=(a-b)(a^2+ab+b^2)

Therefore,


\begin{gathered} 125-27w^3=(5)^3-(3w)^3 \\ \\ \textet a=5,b=3w \\ \\ \Rightarrow(5)^3-(3w)^3=(5-3w)((5)^2+(5)(3w)+(3w)^2) \\ \\ =(5-3w)(25+15w+9w^2) \end{gathered}

User Tylik
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