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A 1,107.64 kg cannon shoots a 51.72 kg cannonball across a field with a velocity of 2.72 m/s. What is the recoil velocity of the cannon?

User NightOwl
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1 Answer

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the recoil velocity of the cannon is 0.12 m/s

Step-by-step explanation

The momentum of the projectile at the instant it was fired is equal to the product of its mass and its velocity (m*v). Then, by conservation of momentum, the cannon must move in the opposite direction with the same momentum

so

conservation of momemtum


\begin{gathered} m_(cannon)v_(cannon)=m_(cannonball)v_(cannonball) \\ \end{gathered}

replace


\begin{gathered} m_(cannon)v_(cannon)=m_(cannonball)v_(cannonball) \\ (1,107.64\operatorname{kg})v_(cannon)=51.72\operatorname{kg}\cdot2.72(m)/(s) \\ 1107.64v_(cannon)=140.6784 \\ divide\text{ both sides by }1107.64 \\ (1107.64v_(cannon))/(1107.64)=(140.6784)/(1107.64) \\ v_(cannon)=0.12\text{ m/s} \end{gathered}

therefore,

the recoil velocity of the cannon is 0.12 m/s

I hope this helps you

A 1,107.64 kg cannon shoots a 51.72 kg cannonball across a field with a velocity of-example-1
User Louisa
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