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Standard Solution and Dilution Dry Post-Lab1.) If you add water to 100 mL of a 0.150M NaOH solution until the final volume is 150 mL, what will be the concentration of the solution be?Round your answer to three significant digits.

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To solve the question, you need to use the following formula


C_1V_1=C_2V_2

where V volumes and C concentrations

Data

C₁=100 mL

V₁= 0.150 M

C₂=

V₂= 150 mL


C_2=(C_1V_1)/(V_2)=\frac{150\text{ M }0.100\text{ mL }}{150\text{ mL}}=0.10\text{ M NaOH}

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