Question

Predict the magnitude of the gravitation force a 66.5kg person would experience while standing on the surface of each of earth. Mass: 5.97x10^24kg radius 6.38x10^6 m

Answer 1

We are given the following information

Mass of person = 66.5 kg

Mass of Earth = 5.97x10^24 kg

Radius of Earth = 6.38x10^6 m

The gravitation force experienced by the person is given by

`F=G\frac{m_{}\cdot M}{r^2}`

Where m is the mass of the person, M is the mass of Earth, r is the radius of Earth and G is the gravitational constant.

G = 6.67430×10⁻¹¹ m³/kg⋅s²

Let us substitute the given values into the above formula

`F=G\frac{m_{}\cdot M}{r^2}=6.67430*10^(-11)(66.5\cdot5.97*10^(24))/((6.38*10^6)^2)=651\; N`

Therefore, the magnitude of the gravitation force is 651 N