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find an equation of the line through (2,5) and parallel to y=3x-6. write the equation using function notation.

User Dmajkic
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1 Answer

3 votes

Answer

y = f(x) = 3x - 1

Step-by-step explanation

The general form of the equation in point-slope form is

y - y₁ = m (x - x₁)

where

y = y-coordinate of a point on the line.

y₁ = This refers to the y-coordinate of a given point on the line

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

x₁ = x-coordinate of the given point on the line

Two lines that are parallel to each other have the same slope.

If the equation of a straight line is written in the form of y = 3x - 6,

,The slope and y-intercept form of the equation of a straight line is given as

y = mx + c

where

y = y-coordinate of a point on the line.

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

c = y-intercept of the line.

So, in y = 3x - 6, the slope = m = 3

So, using the point-slope form,

y - y₁ = m (x - x₁)

m = 3

(x₁, y₁) = (2, 5)

x₁ = 2, y₁ = 5

y - y₁ = m (x - x₁)

y - 5 = 3 (x - 2)

y - 5 = 3x - 6

y = 3x - 6 + 5

y = 3x - 1

In function notation, y = f(x)

So, the equation of the line required is

y = f(x) = 3x - 1

Hope this Helps!!!

User Ruslan Lekhman
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