1 Answer

Qft · Answer 1 · 2023-03-08T16:14:06+0000

$20=95\cdot e^(-0.03t)$

Dividing by 95 at both sides of the equation:

$\begin{gathered} (20)/(95)=(95\cdot e^(-0.03t))/(95) \\ (4)/(19)=e^(-0.03t) \end{gathered}$

Taking natural logarithm at both sides of the equation:

$\begin{gathered} \ln ((4)/(19))=\ln (e^(-0.03t)) \\ \ln ((4)/(19))=-0.03t\cdot\ln (e^{}) \\ \ln ((4)/(19))=-0.03t \end{gathered}$

Dividing by -0.03 at both sides of the equation:

$\begin{gathered} (\ln ((4)/(19)))/(-0.03)=(-0.03t)/(-0.03) \\ (\ln((4)/(19)))/(-0.03)=t \\ 51.94\approx t \end{gathered}$

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