Question

Find the equation of a line that goes through the points (8,9) and (-4, 15).y=-*(1 + 4) + 15Oy=-2(x + 4) + 15Oy=-2(x+8) - 9Oy= } (x – 8) – 9

Answer 1

`\begin{gathered} x_1=8,x_2=-4,y_1=-9,y_2=15 \\ lin\text{e of equation is,} \\ (y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1) \\ (y-9)=(15-(-9))/(-4-8)(x-8) \\ y-9=(24)/(-12)(x-8) \\ y-9=-2(x-8) \\ y-9=-2x+16 \\ y=-2x+9+16 \\ y=-2(x+8)-9 \\ y=-2(x+8)-9 \end{gathered}`