The given information is:
- p=0.05 (the probability of success)
- n=12 (the sample size)
We can apply the binomial distribution formula to find the probabilities. The formula is:
![P(x)=(n!)/((n-x)!x!)p^xq^(n-x)](https://img.qammunity.org/2023/formulas/mathematics/college/d0fgk93cn8q7ygxhbufu4wyou2jk4engmh.png)
q is equal to 1-p, so:
![q=1-0.05=0.95](https://img.qammunity.org/2023/formulas/mathematics/college/zrmclplsc128yp748pk08sduw2ukkkc5wd.png)
a. Find the probability that at least 3 people believe that they have seen a UFO:
This is equal to:
![P(x\ge3)=1-(P(x=0)+P(x=1)+P(x=2))](https://img.qammunity.org/2023/formulas/mathematics/college/66qizyk8aflzmijwbyr8qrlds0g2qdahqa.png)
Let's find the individual probabilities:
![\begin{gathered} P(x=0)=(12!)/((12-0)!1!)*0.05^00.95^(12-0) \\ P(x=0)=1*1*0.5404 \\ P(x=0)=0.5404 \\ \\ P(x=1)=(12!)/((12-1)!1!)*0.05^10.95^(12-1) \\ P(x=1)=12*0.05*0.5688 \\ P(x=1)=0.341 \\ \\ P(x=2)=(12!)/((12-2)!2!)*0.05^20.95^(12-2) \\ P(x=2)=66*0.0025*0.5987 \\ P(x=2)=0.099 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yjsvt8qyvap7pq43ipyh1b9lcwnazvt7jn.png)
So, the P(x>=3) is:
![\begin{gathered} P(x\ge3)=1-(0.5404+0.341+0.099) \\ P(x\ge3)=0.0196 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pzfh02gvxmhr36h98v6ufph9vk7boyqe19.png)
The probability that at least 3 people believe that they have seen a UFO is 0.0196.
b. P(3 or 4 people believe that they have seen a UFO):
This is given by:
![P(3\leq x\leq4)=P(x=3)+P(x=4)](https://img.qammunity.org/2023/formulas/mathematics/college/l219n6udzi4jtg9ixew6qa73elco34e7g8.png)
Let's find the individual probabilities:
![\begin{gathered} P(x=3)=(12!)/((12-3)!3!)*0.05^30.95^(12-3) \\ P(x=3)=220*0.0001*0.6303 \\ P(x=3)=0.0173 \\ \\ P(x=4)=(12!)/((12-4)!4!)*0.05^40.95^(12-4) \\ P(x=4)=495*0.000006*0.663 \\ P(x=4)=0.0021 \\ \\ \text{ So:} \\ P(3\leq x\leq4)=0.0173+0.0021=0.0194 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/eies12pevgurbf6ufpoldpmcm75o5wzx53.png)
The probability that 3 or 4 people believe that they have seen a UFO is 0.0194.
c. P(exactly 2 people believe they have seen a UFO)
This is equal to:
![\begin{gathered} P(x=2) \\ \text{ We already found it in part A, so:} \\ P(x=2)=0.099 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bl1bkutvy86bhj3kftbi9935pvx73g4hnm.png)
The probability that exactly 2 people believe they have seen a UFO is 0.099.