Question

In ΔOPQ, o = 500 cm, p = 600 cm and q=380 cm. Find the measure of ∠P to the nearest 10th of a degree.

Answer 1

Answer: 84.8°

Explanation:

a²+b²+c²-2bc(cosA)

cosA = b² + c² - a² / 2bc

That is the formula we will be using.

Then, plug in our numbers.

cosP= 500² + 380² - 600² / 2(500)(380)

cosP= 34400/380000

cosP≈ 0.09052631

cos⁻¹(0.09052631) ≈ 84.81

∠P = 84.8°