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Does the relation y = √12x + 3 define y as a function of x? Give the domain.

1 Answer

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The function:


y=\sqrt[\placeholder{⬚}]{12x+3}

The domain of this function always is going to be for the values when:


\begin{gathered} 12x+3>=0 \\ Solving\text{ for x} \\ 12x\ge-3 \\ x\operatorname{\ge}-(3)/(12) \end{gathered}

So, the domain is for all values of x equal or greater than -3/12

Domain= R>=-3/12

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