219k views
0 votes
When y varies inversely as the square of x, x = 6 and y = 8. What is x when y = 2?

User Flxkid
by
8.1k points

1 Answer

4 votes

ANSWER

x = 12

Step-by-step explanation

If y varies inversely as the square of x, then it follows this rule:


y=(a)/(x^2)

To find a, we have to use the given point - x = 6 and y = 8 - and solve for a:


\begin{gathered} a=y\cdot x^2 \\ a=8\cdot6^2 \\ a=8\cdot36 \\ a=288 \end{gathered}

Then, the equation is:


y=(288)/(x^2)

Finally, we want to know the value of x when y = 2. Just replace y = 2 in the equation above and solve for x:


\begin{gathered} x=\sqrt{(288)/(y)} \\ x=\sqrt[]{(288)/(2)} \\ x=\sqrt[]{144} \\ x=12 \end{gathered}

User Dvorah
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories