Variables
• x: Number of phone calls the first evening
,
• y: Number of phone calls the second evening
,
• z: Number of phone calls the third evening
Given that Karen received a total of 158 phone calls, then:

Given that in the first evening, she received 8 more calls than the second evening, then:

Given that in the third evening, she received 4 times as many calls as the second evening, then:

Substituting equations 2 and 3 into equation 1 and solving for y:

Substituting y = 25 into equations 2 and 3:

The final answer is:
• Number of phone calls the first evening:, 33
,
• Number of phone calls the second evening: ,25
,
• Number of phone calls the third evening: ,100