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how many terms are in the following sequence:1, 5, 5^2, 5^3, ... 5^30100, 200, 300, 400, ...., 500001, 3, 9, 27, 81, 243, .... 6561

User Rudy S
by
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1 Answer

4 votes

SOLUTION:

Step 1 :

The sequence is a good example of a Geometric Sequence

where


\begin{gathered} l=ar^(n-1) \\ \text{where l = last term = 5}^(30) \\ a\text{ = first term = 5} \\ n\text{ =number of terms = ?} \\ \text{r = common ratio = }(5^2)/(5)\text{ = 5} \end{gathered}

Step 2 :

Putting the values in the equation:


\begin{gathered} 5^(30)\text{ = 5 ( }5)^(n-1) \\ \text{5 }^(30)=5^{1\text{ + n-1 }}=5^n \\ 5^{30\text{ }}=5^n \\ \text{equate the indices, we have that:} \\ n\text{ = 30} \end{gathered}

CONCLUSION :

The number of terms, n = 30.

User MinnuKaAnae
by
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