1 Answer

Eigenharsha · Answer 1 · 2023-09-30T17:36:01+0000

Solution

Consider The following system of equations

2x+y=8

x-2y=-1

$\begin{gathered} 2x+y=8...........(1) \\ x-2y=-1.............(2) \end{gathered}$

using substitution method:

$\begin{gathered} 2x+y=8 \\ y=8-2x.........(3) \end{gathered}$

sub the value of y in equ(2)

$\begin{gathered} x-2y=-1 \\ x-2(8-2x)=-1 \\ x-16+4x=-1 \\ 5x=-1+16 \\ 5x=15 \\ x=(15)/(5) \\ x=3 \end{gathered}$

Sub the value of x in equ(1)

$\begin{gathered} 2x+y=8 \\ 2(3)+y=8 \\ 6+y=8 \\ y=8-6 \\ y=2 \end{gathered}$

Therefore the solution of the equations are

$\begin{gathered} x=3 \\ y=2 \end{gathered}$

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