The figure appears to be a parallelogram with diagonals AC and BD with E as the point of intersection of the two diagonals and also the midpoint.
Diagonal AC has segments AE measuring 3x + 1 and EC measuring x + 25. Since point E is the midpoint of the mentioned diagonal, therefore, we can say that the segments AE and EC should be congruent.
We get,
![\text{ AE = EC}](https://img.qammunity.org/2023/formulas/mathematics/college/o2tvysu13l08as5vn49tzrll6h3ewlu96t.png)
Let's use this relationship to find x.
![\text{ AE = EC}](https://img.qammunity.org/2023/formulas/mathematics/college/o2tvysu13l08as5vn49tzrll6h3ewlu96t.png)
![\text{ 3x + 1 = x + 25}](https://img.qammunity.org/2023/formulas/mathematics/college/ei1akiy5n6i2ylmeshthp21i669b0jepve.png)
![\text{ 3x + 1 - x - 1 = x + 25 - x - 1}](https://img.qammunity.org/2023/formulas/mathematics/college/sft5ba7d3n42f76ai7okce7bg51oq9vgqc.png)
![\text{ 2x = 24}](https://img.qammunity.org/2023/formulas/mathematics/college/scfenwls7ubqnokv4ss6ljgcqwvrsbai3r.png)
![\text{ }\frac{\text{2x}}{2}\text{ = }\frac{\text{24}}{2}](https://img.qammunity.org/2023/formulas/mathematics/college/hizeln0ax5qmargy027j7o9wr8kt2ejwkm.png)
![\text{ x = 12}](https://img.qammunity.org/2023/formulas/mathematics/college/a7zyc38mfcy8nbe8tq5d6vpuvzgmj9eht8.png)
Therefore, x = 12.