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A rhombus with diagonals 15 in and 20 in

User David Liaw
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Given data:

Diagonals if rhombus 15 inches and 20 inches.

Area of rhombus is,


A=(1)/(2)* d1* d2
\begin{gathered} A=(1)/(2)*15*20 \\ A=150\text{inches sq} \end{gathered}

Now, to find the perimeter first find the side of the the rhombus

Diagonal is considered as diameter so radius will be the half of the diameter,

d1 = r1 = 7.5

d2 = r2 = 10

Finding the side by the pythagorean theorem,


\begin{gathered} h^2=(7.5)^2+(10)^2 \\ h^2=56.25+100 \\ h=12.5 \end{gathered}

Therefore, the perimeter of the rhombus is


\begin{gathered} P=4h \\ P=4*12.5 \\ P=50\text{inches} \end{gathered}

Thus, the area is 150 in sq. and perimeter is 50 in.

User Vinniyo
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