141k views
2 votes
What is the slope of a line parallel to the line whose equation is 3x- 18y = -378 Fully simplify your answer.

1 Answer

4 votes

The equation of a line in the slope intercept form is expressed as

y = mx + c

where

m = slope

c = y intercept

The given equation is expressed as

3x - 18y = - 378

We would add 18y to both sides of the equation. We have

3x - 18y + 18y = - 378 + 18y

3x = - 378 + 18y

We would add 378 to both sides of the equation. We have

3x + 378 = - 378 + 378 + 18y

3x + 378 = 18y

18y = 3x + 378

Dividing both sides of the equation by 18, we have

18y/18 = 3x/18 + 378/18

y = x/6 + 21

By comparing this equation with the slope intercept equation,

m = 1/6

Recall, if two lines are parallel, it means that they have the same slope. This means that the slope of a line parallel to the line whose equation is 3x- 18y = - 378 is 1/6

User Dcrosta
by
3.9k points