Question

The area of a semicircle with a diameter of 12.8in.. Round to the nearest tenth

Answer 1

64.3 in²

Step-by-step explanation:

The area of a semicircle can be calculated as:

`A=(\pi* r^2)/(2)`

Where π is approximately 3.14 and r is the radius of the circle.

The radius of the circle is half of the diameter, so the radius of a circle with a diameter of 12.8in is:

`\text{radius = }(Diameter)/(2)=\frac{12.8\text{ in}}{2}=6.4\text{ in}`

Now, we can replace r by 6.4 in on the equation of the Area and get:

`\begin{gathered} A=(3.14*(6.4in)^2)/(2) \\ A=(3.14*40.96in^2)/(2) \\ A=(128.61in^2)/(2) \\ A=64.3in^2 \end{gathered}`

Therefore, the answer is 64.3 in².