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A(n)=-9+(n-1)(6) find the third and 13th term of sequence

User Jignesh
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The recursive formula is:


A(n)=-9+(n-1)(6)

Where n is the n'th term

Third term:

Put n = 3, so we have:


\begin{gathered} A(3)=-9+(3-1)(6) \\ =-9+(2)(6) \\ =3 \end{gathered}

Thirteenth term:

Put n = 13, so we have:


\begin{gathered} A(13)=-9+(13-1)(6) \\ =-9+(12)(6) \\ =63 \end{gathered}

User Matthew Green
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