Question

7. Find the perimeter of the rectangle with length 51 feet and width 77 feet.179 ft128 ft3,927 ft256 ft

Answer 1

The perimeter of a rectangle is given by:

`P=2(W+L)`

Where W= width = 77 ft and L=lenght = 51 ft:

`\begin{gathered} P=2(77ft+51ft) \\ P=2(128ft) \\ P=256ftft \end{gathered}`

Hence, the correct answer is the last option.