108k views
4 votes
The probability distribution of a game is shown in the table. Find the expected number of points won per play. Round to the nearest tenth if needed.0 2 5 101/6. 1/6. 1/2. 1/6a5.7b4.7c4.5d5

1 Answer

1 vote

Solution


\begin{gathered} Expected\text{ }Value=0((1)/(6))+2((1)/(6))+5((1)/(2))+10((1)/(6)) \\ \\ Expected\text{ }Value=(2)/(6)+(15)/(6)+(10)/(6) \\ \\ Expected\text{ }Value=(27)/(6) \\ \\ Expected\text{ }Value=(9)/(2) \\ \\ Expected\text{ }Value=4.5 \end{gathered}

Correct Option C

User Sbleon
by
8.9k points

Related questions

1 answer
4 votes
36.1k views
asked Apr 2, 2019 47.9k views
Kevin Jones asked Apr 2, 2019
by Kevin Jones
7.8k points
1 answer
4 votes
47.9k views
1 answer
4 votes
65.4k views
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories