hello
the points given were

and the equation is parallel to the line

let's rearange this equation

first we find the slope of the line using slope-intercept form
from the equation above, the slope and intercept are

now the equation of the line passing through a point (x1, y1) is given as

now the points of the equation are (3, 1)


the equation of the line is given as y = 3x - 8